f(x) = x²e⁻ˣ
f'(x) = (x²)' * e⁻ˣ + x² * (e⁻ˣ)' = 2x * e⁻ˣ + x² * e⁻ˣ * (-x)' = 2xe⁻ˣ - x²e⁻ˣ
f'(x) = 0
2xe⁻ˣ - x²e⁻ˣ = 0
xe⁻ˣ(2 - x) = 0
e⁻ˣ ≠ 0
x₁ = 0 2 - x = 0
x₂ = 2
Ответ : при x = 0 и x = 2
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f(x) = x²e⁻ˣ
f'(x) = (x²)' * e⁻ˣ + x² * (e⁻ˣ)' = 2x * e⁻ˣ + x² * e⁻ˣ * (-x)' = 2xe⁻ˣ - x²e⁻ˣ
f'(x) = 0
2xe⁻ˣ - x²e⁻ˣ = 0
xe⁻ˣ(2 - x) = 0
e⁻ˣ ≠ 0
x₁ = 0 2 - x = 0
x₂ = 2
Ответ : при x = 0 и x = 2