помогите, пожалуйста, очень срочно. Created by Arina0122. matematika-ru

По формуле:sin α · сos β= (1/2)·(sin( α + β)+ sin (α – β))Уравнение принимает вид:sin(6x)+sin(–2x)=2sin6x–sin2x=2Так как –1 ≤ sin6x ≤ 1;–1 ≤ sin2x ≤ 1.Равенство разности двум возможно только в случае{sin6x=1;{sin2x=–1{6x=πk, k∈ Z ⇒ х=(π/6)·k, {2x=πn, n∈ Z ⇒ x=(π/2)·nНайдем при каких k и n корни одного уравнения равны корням другого.(π/6)·k=(π/2)·nk=3nО т в е т. А)(π/2)·n, n ∈ ZБ) π∈[2; 4] или же:1-2sin^2(2x)+sin2x-1=0, sin2x=t, 2t^2-t=0, t(2t-1)=0, t1=0, t2=1/2 t1=0: sin2x=0, 2x=Пn, x=Пn/2. t2=1/2, sin2x=1/2, 2x=(-1)^k*П/6+Пk, x=(-1)^k*П/12+Пk/2Новые вопросы в Математикаможно с действиями пожалуйста35.628+2.372−316.66÷0.5:(99.479−284.79×0.1)21−0.2×(92.28−91)+73.26÷(10.45−0.45)176×(1.866+3.134−3.77)÷(15.481+1.2−8.681)умоляю, помогите до завтрапомогите пожалуйста ))))Допоможіть виконати завдання номер 19.8....19.9......19.10ПожалуйстаДопоможіть виконати завдання номер 19.6 . 19.7Срочно пожалуйстаПожалуйста, очень прошуУздовж однієї ділянки дороги розтавлено 36 ящиків з піском ,а вздовж другої 16 таких ящиків .На першій ділянціга 100 ц піску більше ,ніж на другій .Ск…ільки піску на кожнійділянці дорогуПжжжжж очень срочноОдин из внешних углов правильного многоугольника равен 40 градусов. Сколько диагоналей имеет данный многоугольник?ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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помогите, пожалуйста, очень срочно...

Arina0122 @Arina0122

July 2022 1 17 Report

помогите, пожалуйста, очень срочно

Answers & Comments

dubovik1999 По формуле:
sin α · сos β= (1/2)·(sin( α + β)+ sin (α – β))

Уравнение принимает вид:
sin(6x)+sin(–2x)=2
sin6x–sin2x=2
Так как
–1 ≤ sin6x ≤ 1;
–1 ≤ sin2x ≤ 1.

Равенство разности двум возможно только в случае

{sin6x=1;
{sin2x=–1

{6x=πk, k∈ Z ⇒ х=(π/6)·k,
{2x=πn, n∈ Z ⇒ x=(π/2)·n

Найдем при каких k и n корни одного уравнения равны корням другого.

(π/6)·k=(π/2)·n
k=3n

О т в е т.
А)(π/2)·n, n ∈ Z
Б) π∈[2; 4]

или же:
1-2sin^2(2x)+sin2x-1=0, sin2x=t,
2t^2-t=0, t(2t-1)=0, t1=0, t2=1/2
t1=0: sin2x=0, 2x=Пn, x=Пn/2.
t2=1/2, sin2x=1/2, 2x=(-1)^k*П/6+Пk, x=(-1)^k*П/12+Пk/2