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ihuyfg
@ihuyfg
November 2021
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snow99
Уравнение касательной:
y = f(x0) + f'(x0)*(x-x0)
f (x0)=f (3) = 4*3^3 + 2*3^2 +3*3 = 108 + 18 + 9 = 135
f'(x) = 12x^2 +4x+3
f'(3) = 12*3^2 + 4*3 + 3 = 108 + 12 + 3 = 123
y= 135 + 123*(x-3) = 123x -234
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Answers & Comments
y = f(x0) + f'(x0)*(x-x0)
f (x0)=f (3) = 4*3^3 + 2*3^2 +3*3 = 108 + 18 + 9 = 135
f'(x) = 12x^2 +4x+3
f'(3) = 12*3^2 + 4*3 + 3 = 108 + 12 + 3 = 123
y= 135 + 123*(x-3) = 123x -234