a) –8(x + 6) = 0
x + 6 = 0 ⇒ x = –6
б) –y(y – 3) = 0
y = 0 ⇒ y₁ = 0
y – 3 = 0 ⇒ y₂ = 3
в) 3(z + 2)(z – 4) = 0
z + 2 = 0 ⇒ z₁ = –2
z – 4 = 0 ⇒ z₂ = 4
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Answers & Comments
a) –8(x + 6) = 0
x + 6 = 0 ⇒ x = –6
б) –y(y – 3) = 0
y = 0 ⇒ y₁ = 0
y – 3 = 0 ⇒ y₂ = 3
в) 3(z + 2)(z – 4) = 0
z + 2 = 0 ⇒ z₁ = –2
z – 4 = 0 ⇒ z₂ = 4