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polinalunina12
@polinalunina12
October 2021
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svin99
В задании ошибка!
Al4C3 + 12H2O = 4Al(OH)3 + 3CH4
n(CH4) = 11.2/22.4 = 0.5 моль
n(Al4C3) = 0.5/3 = 0.167 моль.
масса = 0,167*144 = 24 г.
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Answers & Comments
Al4C3 + 12H2O = 4Al(OH)3 + 3CH4
n(CH4) = 11.2/22.4 = 0.5 моль
n(Al4C3) = 0.5/3 = 0.167 моль.
масса = 0,167*144 = 24 г.