mariyastepanchenko08

Объяснение:

в)10p³-5p⁴+15p8=5p³(2-р+3p⁴)

г) m²+4n-4m-mn= 4(n-m)-m(m-n)=(4-m)(m-n)

flumin

Ответ:

10р³-5р⁴+15р⁸ = 5р³(2-р+3р⁵)

m²+4n-4m-mn = m(m-n)+4(n-m) = m(m-n)-4(m-n) = (m-n)(m-4)