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vae02
@vae02
July 2022
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Помогите пожалуйста!
Представьте в виде произведения:
а) 9(4-х)^2 -16
Найдите корни уравнения:
б) (x+2)^2 -25=0
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ShirokovP
Verified answer
А)
9(4 - x)^2 - 16 = (3(4 - x) - 4) (3(4 - x) + 4) =
= (12 - 3x - 4) (12 - 3x + 4) =
= (8 - 3x) ( 16 - 3x) =
= (3x - 8) (3x - 16)
б)
a^2 - b^2 = (a - b)( a + b)
(x + 2 - 5)( x + 2 + 5) = 0
(x - 3) (x + 7) = 0
x = 3;
x = - 7
2 votes
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Answers & Comments
Verified answer
А)9(4 - x)^2 - 16 = (3(4 - x) - 4) (3(4 - x) + 4) =
= (12 - 3x - 4) (12 - 3x + 4) =
= (8 - 3x) ( 16 - 3x) =
= (3x - 8) (3x - 16)
б)
a^2 - b^2 = (a - b)( a + b)
(x + 2 - 5)( x + 2 + 5) = 0
(x - 3) (x + 7) = 0
x = 3;
x = - 7