1) ...= sinπ/3 = √3/2
2) ...= cos(π+π/4)=-cosπ/4=-√2/2
3) ...=-tgπ/6=-1/√3
4)...=2sin150°+√12*cos210°-(√3)^2=2sin30°-√12*cos30°-3=1-3 -3=-5
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
1) ...= sinπ/3 = √3/2
2) ...= cos(π+π/4)=-cosπ/4=-√2/2
3) ...=-tgπ/6=-1/√3
4)...=2sin150°+√12*cos210°-(√3)^2=2sin30°-√12*cos30°-3=1-3 -3=-5