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repuxova06
@repuxova06
July 2022
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Помогите пожалуйста
Разложить на множители
1)6ах^2-12ах^3;
2)1-4в^2;
3)х^2+8+16;
4)4с(с-2)+(с-2)^2;
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belozerova1955
6ax² - 12ax³=6ax²·(1 - 2x)
1-4b²= 1²- (2b)²= (1-2b)·(1+2b)
x²+8x+16=(x+4)²=(x+4)(x+4)
4c(c-2)+(c-2)² = (c-2)(4c+c-2)= (c-2)(5c-2)
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Answers & Comments
1-4b²= 1²- (2b)²= (1-2b)·(1+2b)
x²+8x+16=(x+4)²=(x+4)(x+4)
4c(c-2)+(c-2)² = (c-2)(4c+c-2)= (c-2)(5c-2)