(2a-b)²-(2a+b)²=4a²-4ab+b²-(4a²+4ab+b²)=-8ab
при
a=1 целая (3/7)= 10/7
b=0,7=7/10
-8ab=-8(10/7)·(7/10)= - 8
c²-ab=(3x-5)²-(x+8)(8-2x)=(9x²-30x+25)-(8x+64-2x²-16x)=
=9x²-30x+25-8x-64+2x²+16x=11x²-22x-39
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Verified answer
(2a-b)²-(2a+b)²=4a²-4ab+b²-(4a²+4ab+b²)=-8ab
при
a=1 целая (3/7)= 10/7
b=0,7=7/10
-8ab=-8(10/7)·(7/10)= - 8
c²-ab=(3x-5)²-(x+8)(8-2x)=(9x²-30x+25)-(8x+64-2x²-16x)=
=9x²-30x+25-8x-64+2x²+16x=11x²-22x-39