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November 2021
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tatianahumanity
(3a³/b²)²=3²·a⁶/b⁴=9a⁶/b⁴
(2x/3y²)·(6y/8x³)=2·6·xy/3·8·x³y²=1/2x²y
(5x²/7y²)÷(10x/14y)=5x²·14y/7y²·10x=x²y/y²x=x/y
(a-3)/4=2, a-3=2·4, a=8+3=11, a=11
(5-x)/(x+2)=0, 5-x=0, x=5
(x-3)(x+2)=0
x-3=0, x₁=3
x+2=0, x₂=-2
(y²-y)/(y-2)·(2y²-4y)/(y²-1)=y(y-1)·2y(y-2)/(y-2)(y-1)(y+1)=2y²/(y+1)
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Answers & Comments
(2x/3y²)·(6y/8x³)=2·6·xy/3·8·x³y²=1/2x²y
(5x²/7y²)÷(10x/14y)=5x²·14y/7y²·10x=x²y/y²x=x/y
(a-3)/4=2, a-3=2·4, a=8+3=11, a=11
(5-x)/(x+2)=0, 5-x=0, x=5
(x-3)(x+2)=0
x-3=0, x₁=3
x+2=0, x₂=-2
(y²-y)/(y-2)·(2y²-4y)/(y²-1)=y(y-1)·2y(y-2)/(y-2)(y-1)(y+1)=2y²/(y+1)