2(-2x^3+3x^2+5x)=(1-3x)x^3-5(0.2x^3-x^2-1)
-4x^3+6x^2+10x = x^2-3x^3-x^3+5x^2+5
Остается 10x=5 => x=1/2
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2(-2x^3+3x^2+5x)=(1-3x)x^3-5(0.2x^3-x^2-1)
-4x^3+6x^2+10x = x^2-3x^3-x^3+5x^2+5
Остается 10x=5 => x=1/2