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steep6
@steep6
July 2022
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Помогите пожалуйста решить логарифмическое уравнение (8)
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MizoriesKun
㏒²₃(x)-3㏒₃(x)-10=0 ОДЗ х>0
замена
㏒₃(x) =t
t²-3t-10=0
D=9+40=49
t=(3+7)/2=5 ㏒₃(x) =5 х=3⁵= 243
t=(3-7)/2=-2 ㏒₃(x) =-2 х=3⁻²=1/3²=1/9
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замена
㏒₃(x) =t
t²-3t-10=0
D=9+40=49
t=(3+7)/2=5 ㏒₃(x) =5 х=3⁵= 243
t=(3-7)/2=-2 ㏒₃(x) =-2 х=3⁻²=1/3²=1/9