ПОМОГИТЕ ПОЖАЛУЙСТА! Решить методом интервалов неравенство:. Created by genri001. algebra-ru

1-3х + 1+3х ≥ 12 1+3х 3х-1 1-9х²1-3х + 1+3х - 12 ≥03х+1 3х-1 1-9х²1-3х + 1+3х + 12 ≥03х+1 3х-1 9х²-11-3х + 1+3х + 12 ≥03х+1 3х-1 (3х-1)(3х+1)(1-3х)(3х-1)+(1+3х)(3х+1)+12 ≥0 (3х-1)(3х+1)-(3х-1)²+(3х+1)²+12 ≥ 0 (3х+1)(3х-1)-(9х²-6х+1)+9х²+6х+1+12 ≥0 (3х+1)(3х-1)-9х²+6х-1+9х²+6х+1+12 ≥0 (3х+1)(3х-1) 12х+12 ≥ 0(3х+1)(3х-1) 12(х+1) ≥0(3х+1)(3х-1){12(x+1)(3x+1)(3x-1) ≥0{3x+1≠0{3x-1≠0{12 * 1 * 1 (x+1)(x+ 1 )(x - 1 ) ≥0 3 3 3 3{x≠ - 1 3{x≠ 1 3(x+1)(x+ 1 )(x- 1 )≥0 3 3x=-1 x=-1 x= 1 3 3 - + - +----------- -1 ---------- - 1 ----------- 1 -------------- \\\\\\\\ 3 3 \\\\\\\\\\\\\\\\x∈[-1; -1 )U ( 1 ; +∞) 3 3 Реклама Реклама Новые вопросы в Алгебра x-1/3+5x+2/12=5+3x/4х пожалуйста помогите мне какому числовому промежутку принадлежат значения "y", если "x" принадлежит [-7;-5] Срочно решите!! даю 100 баллов Упростите выражение 80у – 125y + 180y Упростите выражение (-10А^10 В^4)^2 × (-1 1/3 А ^2 В) ^3 × (0, 75АВ ^3) ^4 упростите выражение √8х+√32 х-√98х упростите выражение 14.4 помогите пожалуйста сор по алгебре 8 класс Предыдущий Следующий Реклама - это не так уж плохо Реклама - это не так уж плохо Понимаем - вы пришли сюда не за рекламой. 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ПОМОГИТЕ ПОЖАЛУЙСТА! Решить методом интервалов неравенство:...

genri001 @genri001

October 2021 1 24 Report

ПОМОГИТЕ ПОЖАЛУЙСТА!
Решить методом интервалов неравенство:

Answers & Comments

m11m 1-3х + 1+3х ≥ 12
1+3х 3х-1 1-9х²

1-3х + 1+3х - 12   ≥0
3х+1 3х-1 1-9х²

1-3х + 1+3х + 12   ≥0
3х+1 3х-1 9х²-1

1-3х + 1+3х +   12 ≥0
3х+1 3х-1 (3х-1)(3х+1)

(1-3х)(3х-1)+(1+3х)(3х+1)+12 ≥0
(3х-1)(3х+1)

-(3х-1)²+(3х+1)²+12 ≥ 0
(3х+1)(3х-1)

-(9х²-6х+1)+9х²+6х+1+12 ≥0
(3х+1)(3х-1)

-9х²+6х-1+9х²+6х+1+12 ≥0
(3х+1)(3х-1)

  12х+12   ≥ 0
(3х+1)(3х-1)

12(х+1) ≥0
(3х+1)(3х-1)

{12(x+1)(3x+1)(3x-1) ≥0
{3x+1≠0
{3x-1≠0

{12 * 1 * 1 (x+1)(x+ 1 )(x - 1 ) ≥0
3     3 3 3
{x≠ - 1
3
{x≠ 1
3

(x+1)(x+ 1 )(x- 1 )≥0
  3    3
x=-1 x=-1 x= 1
  3 3
- + - +
----------- -1 ---------- - 1 ----------- 1 --------------
\\\\\\\\ 3    3 \\\\\\\\\\\\\\\\
x∈[-1; -1 )U ( 1 ; +∞)
  3 3

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