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773kmm
@773kmm
July 2022
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4
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помогите пожалуйста решить номер 3
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MariaArtemyeva
(40+5)+(20-10)=55
(100-70)-10=20
(40+29)-30= 39
80+(2+6)=88
(11+22)+50=83
0 votes
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asaprockikillp4v7eh
А) 40+5+(20-10)=55
б) 100-70-10=20
в)(47-12)+(10-5)=40
г)(40+29)-30=39
д)80+(2+8)=88
е)(11+22)+50=83
1 votes
Thanks 1
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Answers & Comments
(100-70)-10=20
(40+29)-30= 39
80+(2+6)=88
(11+22)+50=83
б) 100-70-10=20
в)(47-12)+(10-5)=40
г)(40+29)-30=39
д)80+(2+8)=88
е)(11+22)+50=83