(2x - 3)' = 2
(x² - 5x + 4)' = 2x - 5
(√x)' = 1 / (2√x)
((x - 3)¹²)' = 12(x - 3)¹¹
(x² - 3x + 4)' = 2x - 3
(x⁴ - 3x² - 7)' = 4x³ - 6x
(3 - 4x)² = 2(3 - 4x)(-4) = -24 + 32x
(1/x)' = -1/x²
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Answers & Comments
(2x - 3)' = 2
(x² - 5x + 4)' = 2x - 5
(√x)' = 1 / (2√x)
((x - 3)¹²)' = 12(x - 3)¹¹
(x² - 3x + 4)' = 2x - 3
(x⁴ - 3x² - 7)' = 4x³ - 6x
(3 - 4x)² = 2(3 - 4x)(-4) = -24 + 32x
(1/x)' = -1/x²