Home
О нас
Products
Services
Регистрация
Войти
Поиск
anya8877
@anya8877
July 2022
1
12
Report
помогите пожалуйста решить! срочно!
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
sedinalana
Verified answer
1
36tgx-27=26tgx+104
10tgx=131
tgx=13,1
x=arctg13,1+πn,n∈z
2
cosx*(cosx-6sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx-6sinx=0/cosx
1-6tgx=0⇒tgx=1/6⇒x=arctg1/6+πk,k∈z
3
6cos²x-1=cosx
cosx=a
6a²-a-1=0
D=1+24=25
a1=(1-5)/12=-1/3⇒cosx=-1/3⇒x=+-(π-arccos1/3)+2πn,n∈z
a2=(1+5)/12=1/2⇒cosx=1/2⇒x=+-π/3+2πk,k∈z
0 votes
Thanks 0
More Questions From This User
See All
anya8877
March 2022 | 0 Ответы
pomogite pozhalujsta reshit srochno ochen nuzhno4678bd034db0e3572ff763add5271d17 34503
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "помогите пожалуйста решить! срочно!..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
136tgx-27=26tgx+104
10tgx=131
tgx=13,1
x=arctg13,1+πn,n∈z
2
cosx*(cosx-6sinx)=0
cosx=0⇒x=π/2+πn,n∈z
cosx-6sinx=0/cosx
1-6tgx=0⇒tgx=1/6⇒x=arctg1/6+πk,k∈z
3
6cos²x-1=cosx
cosx=a
6a²-a-1=0
D=1+24=25
a1=(1-5)/12=-1/3⇒cosx=-1/3⇒x=+-(π-arccos1/3)+2πn,n∈z
a2=(1+5)/12=1/2⇒cosx=1/2⇒x=+-π/3+2πk,k∈z