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maxxx2000
@maxxx2000
August 2022
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Помогите пожалуйста решить уравнение
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Dимасuk
Verified answer
Log₃x + log₉x + log₂₇x = 22/3
log₃x + log₃²x + log₃³x = 22/3
log₃x + 1/2log₃x + 1/3log₃x = 22/3
log₃x(1 + 1/2 + 1/3) = 22/3
log₃x·11/6 = 22/3
log₃x = 4
x = 3² = 81
Ответ: x = 81.
1 votes
Thanks 3
sedinalana
ОДЗ
x>0
log(30x+1/2*log(3)x+1/3*log(3)x=22/3
11/6*log(3)x=22/3
log(3)x=22/3:11/6=22/3*6/11
log(3)x=4
x=81
0 votes
Thanks 2
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Answers & Comments
Verified answer
Log₃x + log₉x + log₂₇x = 22/3log₃x + log₃²x + log₃³x = 22/3
log₃x + 1/2log₃x + 1/3log₃x = 22/3
log₃x(1 + 1/2 + 1/3) = 22/3
log₃x·11/6 = 22/3
log₃x = 4
x = 3² = 81
Ответ: x = 81.
x>0
log(30x+1/2*log(3)x+1/3*log(3)x=22/3
11/6*log(3)x=22/3
log(3)x=22/3:11/6=22/3*6/11
log(3)x=4
x=81