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anjelo4ka
@anjelo4ka
September 2021
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belozerova1955
6cos²x-5sinx+5=0
6(1-sin²x)-5sinx+5=0
6-6sin²x-5sinx+5=0
-6sin²x-5sinx+11=0 (·(-1))
6sin²x+5sinx- 11=0
sinx ========= y
|sinx|≤1
6y²+5y-11=0
D=b²-4ac=25-4·6·(-11)=25+264=289>0, 2корня
y₁=(-5+√289)/(6·2)=(-5+17)/12= 1
y₂=(-5-17)/12=-22/12= - 11/6= -1 5/6 (постор. корень)
sinx=1
x=π/2+2πn, n∈Z
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Answers & Comments
6(1-sin²x)-5sinx+5=0
6-6sin²x-5sinx+5=0
-6sin²x-5sinx+11=0 (·(-1))
6sin²x+5sinx- 11=0
sinx ========= y
|sinx|≤1
6y²+5y-11=0
D=b²-4ac=25-4·6·(-11)=25+264=289>0, 2корня
y₁=(-5+√289)/(6·2)=(-5+17)/12= 1
y₂=(-5-17)/12=-22/12= - 11/6= -1 5/6 (постор. корень)
sinx=1
x=π/2+2πn, n∈Z