Помогите, пожалуйста решить уравнения:
1. (5y+3)^2 - (2y-7)^2 = 8 * (y^2-5)
2. (4+3y)^2 - (5+2y) * (5-2y) = 10+(4y+1)^2
1. (5y+3)^2 - (2y-7)^2 = 8 * (y^2-5)
2. (4+3y)^2 - (5+2y) * (5-2y) = 10+(4y+1)^2
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Answers & Comments
(5y+3)^2 - (2y-7)^2 = 8 * (y^2-5)
25y²+30y+9-4y²+28y-49-8y²+40=0
13y²+58y=0
y(13y+58)=0
y=0
13y+58=0⇒13y=-58⇒y=-58/13
y=-4 6/13
2. (4+3y)^2 - (5+2y) * (5-2y) = 10+(4y+1)^2
16+24y+9y²-25+4y²-10-16y²-8y-1=0
-3y²+16y-20=0
3y²-16y+20=0
D=256-240=16
y1=(16-4)/6=2
y2=(16+4)/6=10/3