А) D = b^2 - 4ac = (-4)*5*(-20) = 400, x1 = (-b+sqrt(D))/2a = 2 x2 = -2
Б) D = b^2 - 4ac = 36, x1 = (-6+6)/6 = 0, x2 = 2;
B) По теореме Виетта: x1 = 8, x2 = -3
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Answers & Comments
А) D = b^2 - 4ac = (-4)*5*(-20) = 400, x1 = (-b+sqrt(D))/2a = 2 x2 = -2
Б) D = b^2 - 4ac = 36, x1 = (-6+6)/6 = 0, x2 = 2;
B) По теореме Виетта: x1 = 8, x2 = -3