Home
О нас
Products
Services
Регистрация
Войти
Поиск
Lerusik450
@Lerusik450
October 2021
1
13
Report
Помогите пожалуйста решить. Вкладка с фотографией.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Anastaramm
Найдем скалярное произведение векторов:
a · b = ax · bx + ay · by
a · b =
3
·
2
+
(-1)
·
4
=
6
-
4
=
2
Длины векторов:
|a| = √ax2 + ay2 = √32 + (-1)2 =
= √9 + 1 = √10
|b| = √bx2 + by2 = √22 + 42 =
= √4 + 16 = √20
=
2√5
Угол между векторами:
cos α =
a · b /
|a||b|
cos α =
√2/10
2 votes
Thanks 1
×
Report "Помогите пожалуйста решить. Вкладка с фотографией..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
a · b = ax · bx + ay · by a · b = 3 · 2 + (-1) · 4 = 6 - 4 = 2
Длины векторов:
|a| = √ax2 + ay2 = √32 + (-1)2 = = √9 + 1 = √10
|b| = √bx2 + by2 = √22 + 42 = = √4 + 16 = √20 =
2√5
Угол между векторами: cos α = a · b / |a||b|
cos α =√2/10