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Lerusik450
@Lerusik450
October 2021
1
14
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Помогите пожалуйста решить. Вкладка с фотографией.
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Anastaramm
Найдем скалярное произведение векторов:
a · b = ax · bx + ay · by
a · b =
3
·
2
+
(-1)
·
4
=
6
-
4
=
2
Длины векторов:
|a| = √ax2 + ay2 = √32 + (-1)2 =
= √9 + 1 = √10
|b| = √bx2 + by2 = √22 + 42 =
= √4 + 16 = √20
=
2√5
Угол между векторами:
cos α =
a · b /
|a||b|
cos α =
√2/10
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Answers & Comments
a · b = ax · bx + ay · by a · b = 3 · 2 + (-1) · 4 = 6 - 4 = 2
Длины векторов:
|a| = √ax2 + ay2 = √32 + (-1)2 = = √9 + 1 = √10
|b| = √bx2 + by2 = √22 + 42 = = √4 + 16 = √20 =
2√5
Угол между векторами: cos α = a · b / |a||b|
cos α =√2/10