Ответ:

дано

m(H2SO4) = 23 g

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m(H2O) - ?

3H2SO4+2Fe(OH)3-->Fe2(SO4)3+6H2O

M(H2SO4) = 98 g/mol

n(H2SO4) = m/M = 23 / 98 = 0.23 mol

3n(H2SO4) = 6n(H2O)

n(H2O) = 0.23*6/3 = 0.46 mol

M(H2O) = 18 g/mol

m(H2O) = n*M =0.46* 18 = 8,28 g

ответ 8.28 г

Объяснение: