2 Al + 3Cl2 = 2AlCl3 M Al = 27г/моль M AlCl3 = 133.5 г/моль m AlCl3 = 133.5*5.4/27 * 0.9 = 24.03 г
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2 Al + 3Cl2 = 2AlCl3 M Al = 27г/моль M AlCl3 = 133.5 г/моль m AlCl3 = 133.5*5.4/27 * 0.9 = 24.03 г