m(р-ра)=280+40=320г
w(C6H12O6)=(40/320)*100%=0,125*100%=12,5%
Ответ:12,5%.
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m(р-ра)=280+40=320г
w(C6H12O6)=(40/320)*100%=0,125*100%=12,5%
Ответ:12,5%.