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anutik7866
@anutik7866
July 2022
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sofyashechenko
|x-y-2/x-3=0
|2x*2+y*2-2xy=13
|x-y-2=0
|2x*2+y*2-2xy=13
|x=y+2
|2x*2+y*2-2xy=13
2(y*2+4y+4)=y*2-2(y+2)*y=13
y=1
y=-5
x=1+2
x=-5+2
x=3
x=-3
(x1,y2)=(3,1)
(x2,y2)=(-3,-5)
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Answers & Comments
|2x*2+y*2-2xy=13
|x-y-2=0
|2x*2+y*2-2xy=13
|x=y+2
|2x*2+y*2-2xy=13
2(y*2+4y+4)=y*2-2(y+2)*y=13
y=1
y=-5
x=1+2
x=-5+2
x=3
x=-3
(x1,y2)=(3,1)
(x2,y2)=(-3,-5)