f(x)=2x², x₀=1
(2x²)`=4x
f`(1)=4
kₓ=4
f(x)=3x²-2x+5, x₀=-1
(3x²-2x+5)`=6x-2
f`(-1)=-8
kₓ=-8
f(x)=8x²+4, x₀=2
(8x²+4)`=16x
f`(2)=32
kₓ=32
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Answers & Comments
f(x)=2x², x₀=1
(2x²)`=4x
f`(1)=4
kₓ=4
f(x)=3x²-2x+5, x₀=-1
(3x²-2x+5)`=6x-2
f`(-1)=-8
kₓ=-8
f(x)=8x²+4, x₀=2
(8x²+4)`=16x
f`(2)=32
kₓ=32