Ответ: tgβ = 6 .
Пошаговое объяснение:
sinβ = - 6/√37 ; βЄ( π ; 3π/2 ) ;
tgβ = sinβ/cosβ ;
cosβ = - √( 1- sin²β ) = - √(1 -( - 6/√37)²) = - √ (1 -36/37 ) = - √( 1/37) = - 1/√37 ;
tgβ = - 6/√37 : ( - 1/√37 ) = 6/√37 * √37 = 6 ; tgβ = 6 .
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Ответ: tgβ = 6 .
Пошаговое объяснение:
sinβ = - 6/√37 ; βЄ( π ; 3π/2 ) ;
tgβ = sinβ/cosβ ;
cosβ = - √( 1- sin²β ) = - √(1 -( - 6/√37)²) = - √ (1 -36/37 ) = - √( 1/37) = - 1/√37 ;
tgβ = - 6/√37 : ( - 1/√37 ) = 6/√37 * √37 = 6 ; tgβ = 6 .