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timosha024
@timosha024
August 2021
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Помогите пожалуйста с 10 на 11 номером
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Айданыч5555
11)m/M=N(N(a) N=m*N(a)/M(N2)=3*10^23 N(N2)=NH2O m=N*Mh2o/N(a)=9 г Ответ 9г. 10)А) оксид алюминий Б) оксид фосфора В) хлорид железа (lll) а)Al2S3 b) P2O5 в)FeCl3
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