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yhnykina
@yhnykina
July 2022
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Помогите пожалуйста с 21 заданием
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TARTILLO
Verified answer
X²-3x+√(3-x)=√(3-x)+10
ОДЗ: 3-x≥0 ⇔x≤3
x²-3x+√(3-x)=√(3-x)+10 ⇔x²-3x-10 =0 x1=5 ∉ОДЗ: 3-x≥0 ⇔x≤3
x2=-2∈ОДЗ: 3-x≥0 ⇔x≤3
ответ:x=-2
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Answers & Comments
Verified answer
X²-3x+√(3-x)=√(3-x)+10ОДЗ: 3-x≥0 ⇔x≤3
x²-3x+√(3-x)=√(3-x)+10 ⇔x²-3x-10 =0 x1=5 ∉ОДЗ: 3-x≥0 ⇔x≤3
x2=-2∈ОДЗ: 3-x≥0 ⇔x≤3
ответ:x=-2