Помогите, пожалуйста, с 7. Created by SunLeeloo. algebra-ru

Помогите, пожалуйста, с 7------------------------Я решил задачи С1. , C2. и C3 . Оказывается (что сомнительно) нужно было решить ТОЛЬКО примитивный B7 .Найдите длину промежутка значений , удовлетворяющих неравенствам sinx ≤ (√2) / 2 и 2π ≤ x ≤ 7π/3 (число π округлите до целых).----------------Получается из решения системы { sinx ≤ (√2) / 2 ; 2π ≤ x ≤ 7π/3 . sinx ≤ (√2) / 2 (простейшее тригонометрическое неравенство)2πn+ π - π/4 ≤ x ≤ 2π+ π/4 + 2πn , n ∈ Z ; см. прикрепленный файл 2πn+3π/4 ≤ x ≤ 9π/4 + 2πn , n ∈ Z ; при n =0 получается 3π/4 ≤ x ≤ 9π/4 * * * 9π/4 =2π +π /4 * * *{3π/4 ≤ x ≤ 9π/4 ; 2π ≤ x ≤7π/3 . ⇒ * * * 7π/3 =2π +π /3 * * * 2π ≤ x ≤ 9π/4 длина этого промежутка будет : 9π/4 - 2π = π/4 =3 / 4= 0,75.---------------- 3π/4//////////////////////////////// 9π/4 ---------------------------------------------------2π ////////////////////////////// 7π/3 ответ : 0,75 .* * * * * * * *Новые вопросы в АлгебраПомогите найти ноль функции[tex](x^3 - 18x)[/tex]Пожалуйста срочно надо спростити вираз (sina*cos5a-cosa*sin 5a)/(cos^2 2a-sin^2 2a)даю сто балов если сделаете Сумма трёх чисел, составляющих арифметическую прогрессию, равна 15, а произведение первого и второго равно 40.Найти эти числаПостройте график функции y = ( x - 2 )²Решить неравенство :Сколько различных двузначных чисел с разными цифрами можно записать, используя цифры 4; 5; 6.Найти четвёртый член геометрической прогрессии, если в1 = 4 ; q = 3Найти значение выражения: 3 корня из 27 отнять 4 корня из 1Найти значение выраженияразложите квадратный трёхчлен на множетели: x в вадрате +х-2ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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6."},{"id":49750760,"content":"\u041d\u0430\u0439\u0442\u0438 \u0447\u0435\u0442\u0432\u0451\u0440\u0442\u044b\u0439 \u0447\u043b\u0435\u043d \u0433\u0435\u043e\u043c\u0435\u0442\u0440\u0438\u0447\u0435\u0441\u043a\u043e\u0439 \u043f\u0440\u043e\u0433\u0440\u0435\u0441\u0441\u0438\u0438, \u0435\u0441\u043b\u0438 \u04321 = 4 ; q = 3"},{"id":49750746,"content":"\u041d\u0430\u0439\u0442\u0438 \u0437\u043d\u0430\u0447\u0435\u043d\u0438\u0435 \u0432\u044b\u0440\u0430\u0436\u0435\u043d\u0438\u044f: 3 \u043a\u043e\u0440\u043d\u044f \u0438\u0437 27 \u043e\u0442\u043d\u044f\u0442\u044c 4 \u043a\u043e\u0440\u043d\u044f \u0438\u0437 1"},{"id":49750737,"content":"\u041d\u0430\u0439\u0442\u0438 \u0437\u043d\u0430\u0447\u0435\u043d\u0438\u0435 \u0432\u044b\u0440\u0430\u0436\u0435\u043d\u0438\u044f"},{"id":49750718,"content":"\u0440\u0430\u0437\u043b\u043e\u0436\u0438\u0442\u0435 \u043a\u0432\u0430\u0434\u0440\u0430\u0442\u043d\u044b\u0439 \u0442\u0440\u0451\u0445\u0447\u043b\u0435\u043d \u043d\u0430 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Помогите, пожалуйста, с 7...

SunLeeloo @SunLeeloo

June 2022 1 16 Report

Помогите, пожалуйста, с 7

Answers & Comments

oganesbagoyan

Verified answer

Помогите, пожалуйста, с 7
------------------------
Я   решил задачи  С1. , C2.  и C3 .
Оказывается (что сомнительно)  нужно было решить ТОЛЬКО примитивный B7 .
Найдите длину промежутка значений , удовлетворяющих неравенствам
sinx ≤ (√2) / 2 и 2π ≤ x ≤ 7π/3 (число   π  округлите до целых).
----------------
Получается из решения системы
{ sinx ≤ (√2) / 2 ;   2π ≤ x ≤ 7π/3 .
sinx ≤ (√2) / 2 (простейшее тригонометрическое неравенство)
2πn+ π - π/4 ≤ x  ≤ 2π+ π/4 +  2πn , n ∈ Z ; см. прикрепленный файл
2πn+3π/4 ≤ x  ≤ 9π/4 +  2πn , n ∈ Z ; при n =0 получается
3π/4 ≤ x  ≤ 9π/4      * * *  9π/4 =2π +π /4 * * *
{3π/4 ≤ x  ≤ 9π/4 ; 2π  ≤ x ≤7π/3 . ⇒   * * *  7π/3 =2π +π /3 * * *
2π  ≤ x ≤  9π/4
длина этого  промежутка будет : 9π/4 - 2π = π/4 =3 / 4= 0,75.
---------------- 3π/4//////////////////////////////// 9π/4 ----------------
-----------------------------------2π ////////////////////////////// 7π/3

ответ : 0,75 .
* * * * * * * *