Помогите пожалуйста с А5 ДАЮ 20 баллов. Created by alsav241357. algebra-ru

Помогите пожалуйста с А5 ДАЮ 20 баллов...

Verified answer

$4 ^{x+1}=2*3 ^{2x+2}+6 ^{x}\\\\4*4 ^{x} -2*9*9 ^{x}-6 ^{x}=0\\\\ \frac{4*4 ^{x} }{4 ^{x} }- \frac{18*9 ^{x} }{4 ^{x} }- \frac{6 ^{x} }{4 ^{x} } =0\\\\[tex]18*( \frac{3}{2}) ^{2x}+( \frac{3}{2} ) ^{x}-4=0$
$18 m^{2} +m-4=0$
$D )= 1-4*18*(-4)= 1+288=289=17 ^{2}$
$m _{1} = \frac{-1+17}{36}= \frac{4}{9}$
$m _{2} = \frac{1-17}{36}=-2$
m = - 2 - не подходит
$(\frac{3}{2}) ^{x}= \frac{4}{9} \\\\( \frac{3}{2} ) ^{x}=( \frac{2}{3}) ^{2}\\\\( \frac{3}{2}) ^{x} =( \frac{3}{2}) ^{-2}\\\\x =-2$

1 votes Thanks 0

sedinalana 4*2^2x-18*3^2x-2^x*3^x=0/3^2x
4(2/3)^2x-(2/3)^x-18=0
(2/3)^x=t
4t²-t-18=0
D=1+288=289
t1=(1-17)/8=-2⇒(2/3)^x=-2 нет решения
t2=(1+17)/8=9/4
(2/3)^x=9/4
x=-2

2 votes Thanks 1

Answers & Comments

Verified answer

esli vtoroj chlen geometricheskoj progressii raven 6 a pyatyj chlen raven 162 to p

pomogite pozhalujsta s a4 i a5 dam 30 ballov

najdite summu semi pervyh chlenov arifmeticheskoj progressii esli eyo vtoroj chlen

esli vershina paraboly yx2byc imeet koordinaty 23 to summa bs ravna chem

pomogite reshit pozhalujsta a7 i a8 dam 40 ballov

vtoroj chlen geometricheskoj progressii raven 6 a pyatyj eyo chlen raven 48 togda s

pomogite pozhalujsta s a5 i a8 dayu 30 ballov

pomogite pozhalujsta s a2 dayu 15 ballov

pozhalujsta pomogite ochen srochno umolyayu s a5 a6 i a7 dayu 35 ballov

bokovoe rebro pravilnoj shestiugolnoj piramidy ravnoe 8 sostavlyaet s vysotoj

рекомендуемые вопросы

Helpful Links

Helpful Social