log3(5+x)=4
ОДЗ: 5+х>0
x>5
log(5+x)=3⁴
5+x=81
x=81-5
x=76
Ответ: 76
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log3(5+x)=4
ОДЗ: 5+х>0
x>5
log(5+x)=3⁴
5+x=81
x=81-5
x=76
Ответ: 76