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kiraklasm1
@kiraklasm1
June 2022
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ПОМОГИТЕ ПОЖАЛУЙСТА С АЛГЕБРОЙ!
Найти критические точки:
y=x^3-6x^2
y=5-2x^2-2x^3-x^4
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Answers & Comments
oldfag1488
1)
y'=3x^2-12x=0
x=0 x=4
2)
y'=-4x-6x^2-4x^3=0
4x^3+6x^2+4x=0
x*(2x^2+3x+2)=0
x=0 x=-1 x=-0.5
2 votes
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Answers & Comments
y'=3x^2-12x=0
x=0 x=4
2)
y'=-4x-6x^2-4x^3=0
4x^3+6x^2+4x=0
x*(2x^2+3x+2)=0
x=0 x=-1 x=-0.5