Home
О нас
Products
Services
Регистрация
Войти
Поиск
elenahegay
@elenahegay
October 2021
1
9
Report
Помогите пожалуйста с алгеброй, вообще не понимаю. Номер 303
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
m11m
1) sin
2π
+ sin
π
= 2 sin
2π+π
cos
2π-π
= 2 sin
3π
cos
π
5 5 5*2 5*2 10 10
2) cos
11π
+ cos
3π
= cos
11π
+ cos
9π
= 2 cos
11π+9π
cos
11π-9π
=
12 4 12 12 12*2 12*2
=2 cos
20π
cos
2π
= 2 cos
5π
cos
π
24 24 6 12
3) cos(π/3 - α) + cosα =2 cos
(π/3 - α+α)
cos (
π/3 -α-α
) =
2 2
=2 cos
π
cos(
π
- α) = 2 *
√3
cos(
π
- α) = √3 cos(
π
- α)
6 6 2 6 6
=√3 (cos
π
cosα + sin
π
sinα) =√3 (
√3
cosα +
sinα
)
6 6 2 2
4) sin(π/6 +α) - sin(π/6 -α) = 2 sin
(π/6 +α-π/6+α)
cos
(π/6 +α+π/6-α)
=
2 2
=2 sinα cosπ/6 = 2 *
√3
sinα =√3 sinα
2
5) sin π/6 - sin π/9 = sin 3π/18 - sin 2π/18 =
= 2 sin
(3π-2π)
cos
(3π+2π)
= 2 sin
π
cos
5π
18*2 18*2 36 36
6) sinα - sin (α +π/3) = 2 sin
(α-α-π/
3) cos
(α+α+π/3)
=
2 2
=2 sin (-π/6) cos(α+π/6) = -2 * (1/2) cos(α + π/6) =
=-cos(α+π/6) = -(cosα cosπ/6 - sinα sin π/6) =
= -(
√3
cosα - (1/2) sinα) =
1
(sinα - √3 cosα)
2 2
1 votes
Thanks 2
More Questions From This User
See All
elenahegay
August 2022 | 0 Ответы
pozhalujsta pomogite perevesti tekst 1991 zhyly azanny 9 kni aza debietini
Answer
elenahegay
July 2022 | 0 Ответы
pomogite perevesti tanysuga bolama prosto na planshete net kazahskoj klaviatur
Answer
elenahegay
February 2022 | 0 Ответы
pomogite pozhalujsta sostavit dialog na kazahskom yazyke zhelatelno s perevodom
Answer
elenahegay
November 2021 | 0 Ответы
pomogite pozhalujsta s zadaniem zaranee ogromnoe spasibo tam i zadaniya i teksty
Answer
elenahegay
October 2021 | 0 Ответы
pomogite pozhalujsta ya voobshe ne ponimayu nomer
Answer
elenahegay
September 2021 | 0 Ответы
pomogite napisat sochinenie na temu o sebe esli nuzhno nemnogo informacii me
Answer
elenahegay
June 2021 | 0 Ответы
pomogite pozhalujsta nomer 1093 ne ponimayu kak ego reshat est predpolozheniya
Answer
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "Помогите пожалуйста с алгеброй, вообще не понимаю. Номер 303..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
5 5 5*2 5*2 10 10
2) cos 11π + cos 3π = cos11π + cos 9π = 2 cos 11π+9π cos 11π-9π =
12 4 12 12 12*2 12*2
=2 cos 20π cos 2π = 2 cos 5π cos π
24 24 6 12
3) cos(π/3 - α) + cosα =2 cos(π/3 - α+α) cos (π/3 -α-α) =
2 2
=2 cos π cos(π - α) = 2 *√3 cos(π - α) = √3 cos(π - α)
6 6 2 6 6
=√3 (cosπ cosα + sinπ sinα) =√3 (√3 cosα + sinα)
6 6 2 2
4) sin(π/6 +α) - sin(π/6 -α) = 2 sin (π/6 +α-π/6+α) cos(π/6 +α+π/6-α) =
2 2
=2 sinα cosπ/6 = 2 * √3 sinα =√3 sinα
2
5) sin π/6 - sin π/9 = sin 3π/18 - sin 2π/18 =
= 2 sin (3π-2π) cos (3π+2π) = 2 sin π cos 5π
18*2 18*2 36 36
6) sinα - sin (α +π/3) = 2 sin (α-α-π/3) cos (α+α+π/3) =
2 2
=2 sin (-π/6) cos(α+π/6) = -2 * (1/2) cos(α + π/6) =
=-cos(α+π/6) = -(cosα cosπ/6 - sinα sin π/6) =
= -(√3 cosα - (1/2) sinα) =1 (sinα - √3 cosα)
2 2