Помогите, пожалуйста с Алгеброй!!! . Created by HappyShanni. algebra-ru

Помогите, пожалуйста с Алгеброй!!! ...

Объяснение:

$a)\ -4^{n+1}=-4*4^n=-4*2^{2n}=-4*(2^n)^2=-4a^2.\\b)\ -4^{n+3}=-4^3*4^n=-64*2^{2n}=-64*(2^n)^2=-64a^2.\\c)\ 4^{n+3}*(-1)^3=-4^3*4^n=-64*2^{2n}=-64*(2n)^2=-64a^2.\\d)\ 4^{n+3}-39a=4^3*4^n-39a=64*4^n-39a=64*(2^n)^2-39a=\\=64a^2-39a=a*(64a-39).$

0 votes Thanks 1

sangers1959

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Ответ:

а) -2 2n+2(степень)

б) -2 2n+6(степень)

в) -4 n+2(степень)

Четвёртое не знаю, прости. Я сама не уверена правильно ли это

Объяснение:

2 votes Thanks 1

HappyShanni а в последнем какой ответ?

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