Помогите, пожалуйста, с алгеброй. Created by Аннабелла26. algebra-ru

12x-1=272x=28x=142ОДЗ{2x-6≥0⇒x≥3{x+4≥0⇒x≥-4{5-√x+4≥0⇒√x+4≤5≤25⇒x≤21x∈[3;21]возведем в квадрат обе части2x-6=25-10√(x+4)+x+410√x+4=29+x-2x+610√x+4=35-x100(x+4)=1225-70x+x²x²-70x+1225-100x-400=0x²-170x+825=0D=28900-3300=25600x1=(170-160)/2=5x2=(170+160)/2=165 не удов усл3Разделим на сos²xatg²x+btgy+c=0tgx=yay²+by+c=0D=b²-4ac1)D<0 нет решения2)D=0y=-b/a⇒tgx=-b/a⇒x=-arctgb/a+πn,n∈z3)D>0y1=(-b-√D)/2a⇒tgx=(-b-√d)/2a⇒x=arctg(-b-√d)/2a+πn,n∈zy2=(-b+√D)/2a⇒tgx=(-b+√d)/2a⇒x=arctg(-b+√d)/2a+πn,n∈z Реклама Реклама Новые вопросы в Алгебра Можно с объяснением, пожалуйста. но не из photomath помогите пожалуйста, алгебра 9 класс. ДОПОМОЖІТЬ БУДЬ ЛАСКА З ФУНКЦІЄЮ(даю 100 балів)!!!з поясненням 5x-1+3x²^=3x помогите пж рещать уравнение хелп/ x/3b-√x sin x,если 1<=x<=2 F = (ax+b)/atg x,если x<1 x2 - eax ,если x>2 a=2,67; b=9,31; x=cos(3a+b) Решите пожалуйста на языке с++ 3.1. Доведіть, що при а2 -2 виконується нерівність а³+8>‐2а²+ 4а.пожалуйстааааааа кажи все натуральные решения неравенства: −8≤x<7. Ответ: x= Задание на фотографии: Спростити вираз Допоможіть, будь-ласка, даю 30 баллів:|[tex]x\\-\\2[/tex] + 3| ⩾ x|2x -5| ⩽ x + 2|x² - 15| ⩾ 2x|6 - x²| ⩽ x ................................. Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Помогите, пожалуйста, с алгеброй...

Аннабелла26 @Аннабелла26

October 2021 1 37 Report

Помогите, пожалуйста, с алгеброй

Answers & Comments

sedinalana

Verified answer

1
2x-1=27
2x=28
x=14
2
ОДЗ
{2x-6≥0⇒x≥3
{x+4≥0⇒x≥-4
{5-√x+4≥0⇒√x+4≤5≤25⇒x≤21
x∈[3;21]
возведем в квадрат обе части
2x-6=25-10√(x+4)+x+4
10√x+4=29+x-2x+6
10√x+4=35-x
100(x+4)=1225-70x+x²
x²-70x+1225-100x-400=0
x²-170x+825=0
D=28900-3300=25600
x1=(170-160)/2=5
x2=(170+160)/2=165 не удов усл
3
Разделим на сos²x
atg²x+btgy+c=0
tgx=y
ay²+by+c=0
D=b²-4ac
1)D<0 нет решения
2)D=0
y=-b/a⇒tgx=-b/a⇒x=-arctgb/a+πn,n∈z
3)D>0
y1=(-b-√D)/2a⇒tgx=(-b-√d)/2a⇒x=arctg(-b-√d)/2a+πn,n∈z
y2=(-b+√D)/2a⇒tgx=(-b+√d)/2a⇒x=arctg(-b+√d)/2a+πn,n∈z