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yagodka00
@yagodka00
March 2022
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помогите пожалуйста с аогеброй
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dasdasfa
1) Перейдём к основанию 2!
(1/2)^(3*(2x^2/3)) =2^(-2x) *((2^3)(-4))
2^(-(2x^2))=2^(-2x-12)
-2x^2=-2x-12
-2x^2+2x+12=0; x^2-x-6=0; x=3 ili x=-2 Ответ.-2;3.
2)3^(x^2)=27*(3^(2x)
3^(x^2)=3^3) *3^(2x)
3^(x^2)=3^(3+2x)
x^2=3+2x; x^2-2x-3=0; x=3 ili x=-1
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Answers & Comments
(1/2)^(3*(2x^2/3)) =2^(-2x) *((2^3)(-4))
2^(-(2x^2))=2^(-2x-12)
-2x^2=-2x-12
-2x^2+2x+12=0; x^2-x-6=0; x=3 ili x=-2 Ответ.-2;3.
2)3^(x^2)=27*(3^(2x)
3^(x^2)=3^3) *3^(2x)
3^(x^2)=3^(3+2x)
x^2=3+2x; x^2-2x-3=0; x=3 ili x=-1