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ludinova2012
@ludinova2012
July 2022
2
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Помогите Пожалуйста с физикой!!
Определить абсолютную температуру Газа, соответствующую температуре по шкале Цельсия 23С; 136C; 405C
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T1=273+23=296 K
T2=273+136=409 K
T3=273+405=678 K
======================
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fatt52
Verified answer
T=t+273
Т1=23+273=296 К
Т2=136+273=409 К
Т3=405+273=678 К
0 votes
Thanks 0
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Answers & Comments
T2=273+136=409 K
T3=273+405=678 K
======================
Verified answer
T=t+273Т1=23+273=296 К
Т2=136+273=409 К
Т3=405+273=678 К