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Nastya2100
@Nastya2100
July 2022
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Помогите, пожалуйста, с номером 12(3)
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aksii
Сos (x)cos(2x)sin(3x)= sin2x/4
cos(x) cos(2x) sin(3x)= 1/4 sin(2x)
cos(x) cos(2x) sin(3x) - 1/4 sin(2x) =0
1/4 (4 cos (x) cos (2x) sin(3x)-sin(2x))=0
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Answers & Comments
cos(x) cos(2x) sin(3x)= 1/4 sin(2x)
cos(x) cos(2x) sin(3x) - 1/4 sin(2x) =0
1/4 (4 cos (x) cos (2x) sin(3x)-sin(2x))=0