jama9508
14.log(2)24/log(96)2-log(2)192/log(12)2=log(2)24*log(2)96-log(2)192*log(2)12=log(2)[8*3]*log(2)[32*3]-log(2)[64*3]*log(2)[4*3]=(log(2)8+log(2)3)*(log(2)32+log(2)3)-(log(2)64+log(2)3)*(log(2)4+log(2)3)=(3+log(2)3)*(5+log(2)3)-(6+log(2)3)*(2+log(2)3)=15+3log(2)3+5log(2)3+(log(2)3)^2-12-6log(2)3-2log(2)3-(log(2)3)^2=3 15)log(3)15/log(225)9-log(3)45/log(5)3=log(3)15*log(9)225-log(3)45*log(3)5=log(3)15*log(3)15-log(3)[9*5]*log(3)5=(log(3)[3*5])^2-(log(3)9+log(3)5)*log(3)5=(log(3)3+log(3)5)^2-(2+log(3)5)*log(3)5=1+2log(3)5+(log(3)5)^2-2log(3)5-(log(3)5)^2=1 16)(log(3)4+log(4)3+2)*log(3)16*(log(3)144)^2=(log(3)4+1/log(4)3+2)*2*log(3)4*(log(3)[9*16])^2=2*((log(3)4)^2+2log(3)4+1)*(log(3)9+log(3)16)^2=2*(log(3)4+1)^2*(2+2log(3)4)^2=8*(log(3)4+1)^4=8*(2log(3)2+1)^4извиняюсь, что долго. Писал на телефоне)
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Использованы свойства логарифмов15)log(3)15/log(225)9-log(3)45/log(5)3=log(3)15*log(9)225-log(3)45*log(3)5=log(3)15*log(3)15-log(3)[9*5]*log(3)5=(log(3)[3*5])^2-(log(3)9+log(3)5)*log(3)5=(log(3)3+log(3)5)^2-(2+log(3)5)*log(3)5=1+2log(3)5+(log(3)5)^2-2log(3)5-(log(3)5)^2=1
16)(log(3)4+log(4)3+2)*log(3)16*(log(3)144)^2=(log(3)4+1/log(4)3+2)*2*log(3)4*(log(3)[9*16])^2=2*((log(3)4)^2+2log(3)4+1)*(log(3)9+log(3)16)^2=2*(log(3)4+1)^2*(2+2log(3)4)^2=8*(log(3)4+1)^4=8*(2log(3)2+1)^4извиняюсь, что долго. Писал на телефоне)