Ответ:
1. B; 2. B
Пошаговое объяснение:
1. (a-b)(a+b)=a^2-b^2
(a-b)^2(a+b)^2=(a^2-b^2)^2(a^2-b^2)^2 => такая же тема и с дробными степенями:
(a-b)^(1/2)(a+b)^(1/2)=(a^2-b^2)^(1/2)(a^2-b^2)^(1/2)
(9-17^(1/2))^(1/6)(9+17^(1/2))^(1/6)=(81-17)^(1/6)=
=(64)^(1/6)=(2^6)^(1/6)=2^(6/6)=2
2. (n^2/(9m))^(1/3)/(3m^2/n/)^(1/3)=
=(n^2/(9m)*n/(3m^2/)^(1/3)=
=(n^3/(27m^3))^(1/3)=
=(n^3/((3m)^3))^(1/3)=
=(n/((3m))^(3/3)=
=n/(3m)
вроде так, 3 задание, хз
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Answers & Comments
Ответ:
1. B; 2. B
Пошаговое объяснение:
1. (a-b)(a+b)=a^2-b^2
(a-b)^2(a+b)^2=(a^2-b^2)^2(a^2-b^2)^2 => такая же тема и с дробными степенями:
(a-b)^(1/2)(a+b)^(1/2)=(a^2-b^2)^(1/2)(a^2-b^2)^(1/2)
(9-17^(1/2))^(1/6)(9+17^(1/2))^(1/6)=(81-17)^(1/6)=
=(64)^(1/6)=(2^6)^(1/6)=2^(6/6)=2
2. (n^2/(9m))^(1/3)/(3m^2/n/)^(1/3)=
=(n^2/(9m)*n/(3m^2/)^(1/3)=
=(n^3/(27m^3))^(1/3)=
=(n^3/((3m)^3))^(1/3)=
=(n/((3m))^(3/3)=
=n/(3m)
вроде так, 3 задание, хз