Ответ:

0

Объяснение:

eq1(sin(x/3)+x^2)dx

eq2(sin(x/3)+x^2)dx

eq2=3cos(x/3)+(x^3)/3

eq1= -3cos(x/3)+(x^3)/3)

eq1=-3cos(2/3)+8/3 -(-3cos(1/3)+1/3)

eq2=3cos(1/3)+1/3-(3cos(2/3)+8/3)

eq1+eq2=6cos(1/3)-6cos(2/3)

=6*(cos(1/3)-cos(2/3))

cos1/3= about cos 0.33 =1

cos2/3 =about cos 0.66=1

6*(1-1)=0