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@0620
July 2022
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Помогите пожалуйста с В6, с решением
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NNNLLL54
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АС=ВС ---> ΔABC - равнобедренный ---> <BAC=<ABC---> tg<BAC=tg<ABC=2
ΔABH: tgABH=tgABC=AH/BH=2=2/1 ---> tgBAH=BH/AH=1/2
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АС=ВС ---> ΔABC - равнобедренный ---> <BAC=<ABC---> tg<BAC=tg<ABC=2ΔABH: tgABH=tgABC=AH/BH=2=2/1 ---> tgBAH=BH/AH=1/2