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БейтсонГрегори
@БейтсонГрегори
November 2021
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Помогите пожалуйста с выражением
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m11m
Решение:
1) ⁵√²⁸√а = (а^(1/28))^(1/5) = a^(1/28 * 1/5) = a^(1/140)
2) ⁷√²⁰√a = (a^(1/20))^(1/7) = a^(1/20 * 1/7) =a^(1/140)
3) ³⁵√⁴√a =(a^(1/4))^(1/35) = a^(1/4 * 1/35) = a^(1/140)
4)
15 a^(1/140) - 7a^(1/140)
=
8a^(1/140)
= 4
2a^(1/140) 2^(1/140)
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Answers & Comments
1) ⁵√²⁸√а = (а^(1/28))^(1/5) = a^(1/28 * 1/5) = a^(1/140)
2) ⁷√²⁰√a = (a^(1/20))^(1/7) = a^(1/20 * 1/7) =a^(1/140)
3) ³⁵√⁴√a =(a^(1/4))^(1/35) = a^(1/4 * 1/35) = a^(1/140)
4) 15 a^(1/140) - 7a^(1/140) = 8a^(1/140) = 4
2a^(1/140) 2^(1/140)