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anastasiagomen
@anastasiagomen
August 2022
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Помогите, пожалуйста
sin*x+1,5sin2x-3cos*x=1
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margovaskovez
sin*x+1,5sin2x-3cos*x=1.
sin*x+1,5*2sin*x*cosx-3cos*x=1
sin*x+3sin*x*cosx-3cos*x=1. Погрупуємо і винесемо спільне за дужки.
(sin*x-1) + 3cosx(sinx-1)=0
(sin*x-1) (1+3cosx)=0; sin*x-1=0; sin*x=1 ; x= pi/2+2pi*n, n єZ.
1+3cosx=0; 3cosx=-1; cosx=-1/3; x=+-arccos1/3 +2*pi*n, n єZ
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Answers & Comments
sin*x+1,5*2sin*x*cosx-3cos*x=1
sin*x+3sin*x*cosx-3cos*x=1. Погрупуємо і винесемо спільне за дужки.
(sin*x-1) + 3cosx(sinx-1)=0
(sin*x-1) (1+3cosx)=0; sin*x-1=0; sin*x=1 ; x= pi/2+2pi*n, n єZ.
1+3cosx=0; 3cosx=-1; cosx=-1/3; x=+-arccos1/3 +2*pi*n, n єZ