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nuuuun
@nuuuun
July 2022
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Помогите пожалуйста со 2 задачей
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kelpyru
L = Lo/2
L= Lo*√1 -V^2/C2
1/2= √1- V^2/C2
1/4= 1 - V^2/C^2
V^2/C^2=0,75
V=0,866*C - ответ
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Answers & Comments
L= Lo*√1 -V^2/C2
1/2= √1- V^2/C2
1/4= 1 - V^2/C^2
V^2/C^2=0,75
V=0,866*C - ответ