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mlsgywabb
@mlsgywabb
August 2022
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Помогите пожалуйста , срочно.
1 и 2 задание
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selmash21
1.
а)=2р/3х^4
б)=9у^2/3у(2+у)=3у/(2+у)
в)=(5-с)(5+с)/(5+с)=5-с
2.
а)=(2(10б+3)-3(б+2))/36б=
=(20б+6-3б-6)/36б=
=17б/36б=17/36
б)=(2х(х-6)+2х(х+6))/(х+6)(х-6)=
=(2х^2-12х+2х^2+12х)/(х^2-36)=
=4х^2/(х^2-36)
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Answers & Comments
а)=2р/3х^4
б)=9у^2/3у(2+у)=3у/(2+у)
в)=(5-с)(5+с)/(5+с)=5-с
2.
а)=(2(10б+3)-3(б+2))/36б=
=(20б+6-3б-6)/36б=
=17б/36б=17/36
б)=(2х(х-6)+2х(х+6))/(х+6)(х-6)=
=(2х^2-12х+2х^2+12х)/(х^2-36)=
=4х^2/(х^2-36)