Ответ:
1) ; 2) ; 3) ; 4) ; 5)
Объяснение:
1) +=
=
+=
5x-7=(x+2)a+(x-2)b
=5x--7=Ax+2a+Bx-2b=
5x-7=Ax+Bx+2a-2b=
5x-7=(a+d)x+(2s-2b)=
(=
2) =
3) =
4) , при a=2; b=-3
5) =
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Answers & Comments
Ответ:
1)
; 2)
; 3)
; 4)
; 5) 
Объяснение:
1)
+
=
5x-7=(x+2)a+(x-2)b
=5x--7=Ax+2a+Bx-2b=
5x-7=Ax+Bx+2a-2b=
5x-7=(a+d)x+(2s-2b)=
(
=
Ответ:
2)
=
Ответ:
3)
=
Ответ:
4)
, при a=2; b=-3
Ответ:
5)
=
Ответ: