Ответ:
1) y(x+1) + z(x+1)= (y+z)(x+1)
2)y(x-1) + z(x-1) = (y+z)(x-1)
3)m(k+1) + n(k+1)=(m+n)(k+1)
4)m(1-k)+n(k-1)=(m-n)(1-k)
5)m(1-k)+n(k-1)=(m+n)(1-k)
6)m(-1+k)+n(k-1)=(m+n)(k-1)
7)n(m+5)+k(m+5)=(n+k)(m+5)
8)n(m-2)+k(-2+m)=(n+k)(m-2)
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Answers & Comments
Ответ:
1) y(x+1) + z(x+1)= (y+z)(x+1)
2)y(x-1) + z(x-1) = (y+z)(x-1)
3)m(k+1) + n(k+1)=(m+n)(k+1)
4)m(1-k)+n(k-1)=(m-n)(1-k)
5)m(1-k)+n(k-1)=(m+n)(1-k)
6)m(-1+k)+n(k-1)=(m+n)(k-1)
7)n(m+5)+k(m+5)=(n+k)(m+5)
8)n(m-2)+k(-2+m)=(n+k)(m-2)